पृष्ठम्:महाभास्करीयम्.djvu/१२२

WEBK-DAY PULVERISER 37 ahargana calculated (for the given day) gives the ahargana for the required day¹. This rule will become clear by the following solved example. Example. "The mean longitude of the Sun (for sunrise) on a Wednesday is stated to be 8 signs, 25 degrees, 36 minutes, and 10 seconds. Say correctly after how much time (since the beginning of Kaliyuga) will the Sun again assume the same position (at sunrise) on a Thursday, Friday, and Wednesday." We first determine the ahargana elapsed at sunrise on Wednesday when the Sun's mean longitude 8 signs, 25 degrees, 36 minutes, and 10 seconds. Since the Sun's mean longitude = 8 signs 25° 36' 10" 956170", therefore, by stanza 46(ii), the residue of revolutions Thus we have to solve the pulveriser 576 x 155222 210389 = }, 1000, 155222. where x is the ahargana and y the revolutions performed by the Sun. Solving this equation, we obtain y = 2. Hence the ahargana for the given Wednesday <= 1000. (i) Now we find out the ahargana elapsed at sunrise on a Thursday when the Sun again occupies the same position. Let the required ahargana be 1000+A. Then in A days the Sun will describe complete revolutions. Also since Thursday is in advance of ¹ The text is a little obscure at this place. Our translation is based on the interpretations given by the commentators. It also agrees with the details of the rule supplied by the author Bhaskara I himself in his commen- tary on A, ii. 32-33. 2 Bhāskara I's example occurring in his comm, on A, ii. 32-33.