पृष्ठम्:Ganita Sara Sangraha - Sanskrit.djvu/३६२

164 GANITASAR SANGRAH.A. that sum). The resulting product is (then) halved and (then) squared. (From this squared quautity), the (above-referred-to possible) excess quantity is subtracted. The result is divided by four, and then combined with one. Then the resulting quantity is either added to or subtracted from (respectively) by the half of the difference between the two given quantities as diminished or increased by the odd-making excess quantity (above referred to) according as the original given quantity to be subtracted is greater or less than the original given quantity to be added. The result arrived at in this manner happens to be the (required) number, which (when associated as desired with the (given) quantities) surely yields the square root (exactly). Examples in illustration thereof. 276. A certain number when increased by 10 or decreased by 17 yields an exact square root. If possible, O arithmetician, tell me quickly that number. 277. A certain quantity either as diminished by 7, or as added to by 18, yields the square root exactly. O arithmetician, give it out after calculation. 278. A certain quantity dimmished by, or again that same (quantity) increased by, yields the square root (exactly) Tell me that quantity quickly, O arithmetician, after thinking out what it may be. The nationale of this may be made out thus - (n + 1)² n² = 2n + 1, an odd number, and (n + 2)² n² = 4 n + 4, an oven number; where n is any integer. From 2 + 1, and 4 m + 4, the rule shows how we may arrive at na when we know 2n + 1, or in + 4, to be equal to a + b. 278 Since the quantities represented by b and a in the note on stanza 2751 are seen to be fractional in this picblem, being actually and, it is necessary to have these fractional quantities removed from the process of working out the problem in accordance with the given rule. For this purpose they are first reduced to the same denominator, and come to be represented by and respectively then these quantities are multiplied by (21)2, so as to yield 294 and 189, which are assumed to be the b and the a in the problem The result arrived at with these assumed values of b and a is divided by (21)³, and the quotient is taken to be the answer of the problem,