GANITASĀRASANGRAHA. (then) divided by their sum. The (resulting) quotients, on being multiplied by the measure of the base (as a whole) give rise to the (respective basal) segments. These (measures of the segments respectively) multiplied in the inverse order by the quotients (obtained in the first instance as above), give rise (in each case) to the value of the inner, perpendicular. 244 Examples in illustration thereof. 181 (The given) pillars are 16 hastas in height The base (covering the length between the points where the strings touch the ground) is poi out to be 16 hastus. Give out, in this case, the numerical value of the segments of the base and also of the inner perpendicular. 1824. The height of one pillar is 36 hastas; that of the second is 20 hastas. The length of the base-line is 12 hastas. What is the measure of the (basal) segments and what of the (inner) perpendicular? 183-184. (The two pillars are) 12 and 15 hastas (respect- ively); the measure of the interval between the two pillars is 4 hastas. From the top of the pillar of 12 hastas a string is stretched so as to cover 4 hastas (along the basal line) beyond the foot of the other pillar. From the top of (this) other pilla (which is 15 hastas in height) a string is (similarly) stretched so as to cover 1 hasta (along the basal line) beyond the foot (of the pillar of 12 hastas in height). What is the measure of the (basal) segments here, and what of the inner perpendicular? 185. (In the case of a quadrilateral with two equal sides), each of the two sides is 13 hastas in measure. The base here is 14 From these ratios we get a (c + m) b (c+n) C₂ a (c + m)
- C₂ =
, and p= c₂ x a c+n b c + m. C1 C1+ C₂ a (c + m) + b(c + n) ³ b(c+n) (c+m+n) Similarly c₂=. or C₁ x a (c+m) +b (c+n) 185. Here a quadrilateral with two equal sides is given, in the next stanza a quadrilateral with three equal sides, and in the one next to it a quadrilateral with unequal sides are given. In all these cases the diagonals of the quadri- lateral have to be first found out in accordance with the rule given in stanza ..". a (c+m) (c+m+n) a (c+m) +b(c+n)
